(3x^2-4x^2+7x-3)-(4x-2/3x^2+2)=0

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Solution for (3x^2-4x^2+7x-3)-(4x-2/3x^2+2)=0 equation:


x in (-oo:+oo)

3*x^2-(4*x^2)+(2/3)*x^2+7*x-(4*x)-3-2 = 0

3*x^2-4*x^2+(2/3)*x^2+7*x-4*x-3-2 = 0

3*x-1/3*x^2-5 = 0

DELTA = 3^2-(-5*(-1/3)*4)

DELTA = 7/3

DELTA > 0

x = ((7/3)^(1/2)-3)/(-1/3*2) or x = (-(7/3)^(1/2)-3)/(-1/3*2)

x = -3/2*((7/3)^(1/2)-3) or x = 3/2*((7/3)^(1/2)+3)

x in { -3/2*((7/3)^(1/2)-3), 3/2*((7/3)^(1/2)+3) }

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